Sunday, 31 March 2013

Tuesday, 26 March 2013

Define the term line clipping. The parametric equation of line PQ may be defined as P + t (Q-P) where 0 ≤ t ≤ 1. Explain this equation with the help of an example. Derive the expression for t with respect to ith edge and PQ (line to be clipped) in the context of Cyber Beck line clipping algorithm. How will you determine whether a point is PE or PL in Cyrus Beck line clipping algorithm.

Define the term line clipping. The parametric equation of line PQ may be defined as P + t (Q-P) where 0 ≤ t ≤ 1. Explain this equation with the help of an example. Derive the expression for t with respect to ith  edge and PQ (line to be clipped) in the context of Cyber Beck line clipping algorithm. How will you determine whether a point is PE  or PL in Cyrus Beck line clipping algorithm.




Wednesday, 20 March 2013

MDB (Message Driven Bean) for news agency

Write a MDB (Message Driven Bean) for news agency that has to
capture the data from various news sources. The newly written MDB
should accept the XML format of the news. The XML data needs to be
parsed and stored in the database. The news format is as follows:
 
<news_id> </ news_id>
<sources> </source>
<date> </date>
<type_of_news> </type_of_news>
<priority> <priority>
<news_content> </news_content>


import java.util.Date;
import java.util.DateFormat;
import java.util.SimpleDateFormat;
import javax.jms.*;
import org.w3c.dom.Document;
import java.sql.*;

private class News{
    private int id;
    public int priority;
    public date;
    public String sources="",type_of_news,news_content;   
    public News(int id){
        this.id=id;
    }
    public int getID(){
        return id;
    }
}


Public class NewsMDB implements MessageDrivenBean,MessageListener {

    private NewsLocal news;
    private Document dom;

    public void setMessageDrivenContext(MessageDrivenContext mdc) {
        try {
            InitialContext ictx = new InitialContext();
        } catch ( Exception ex ) {
            throw new EJBException("Unable to get News Agency bean", ex);
        }
    }
    public void ejbCreate() { }
    public void ejbRemove() { }
    public void onMessage(Message msg) {
        XMLMessage xml = (XMLMessage)msg;
        try {
            dom=xml.getDocument();
            saveInDB(parseDocument());
        } catch ( Exception ex ) {
            throw new EJBException(ex);
        }
    }
    private void saveInDB(News ns){
        try{
            Class.forName("");//Class required for DataBase
            DriverManager.getConnection("","",""); //Database file path & Userid/password
            PreparedStatement st;
            st=con.createPreparedStatement("Insert into news values(?,?,?,?,?,?)");
            st.setInt(1,ns.getID());
            st.setString(2,ns.sources);
            st.setDate(3,ns.date);
            st.setString(4,ns.type_of_news);
            st.setInt(5,ns.priority);
            st.setString(6,ns.news_content);
            st.execute();
            st.close();
            st=null;
            con.close();
            con=null;
        }catch(SQLException se){
            throw new EJBException("Unable to Save News Agency bean", ex);
        }
    }
    private News parseDocument(){
        Element docEle;
        News news;
        //get the root element
        docEle = dom.getDocumentElement();
        //get a nodelist of elements
        int id=getIntValue(docEle,"news_id");
        news=new News(id);
        news.sources=getIntValue(docEle,"sources");
        news.date=getDateValue(docEle,"date");
        news.type_of_news=getStringValue(docEle,"type_of_news");
        news.priority=getIntValue(docEle,"priority");
        news.news_content=getStringValue(docEle,"news_content");
        return news;
    }
   
    private String getTextValue(Element ele, String tagName) {
        String textVal = null;
        NodeList nl = ele.getElementsByTagName(tagName);
        if(nl != null && nl.getLength() > 0) {
            Element el = (Element)nl.item(0);
            textVal = el.getFirstChild().getNodeValue();
        }
        return textVal;
    }
    private int getIntValue(Element ele, String tagName) {       
        return Integer.parseInt(getTextValue(ele,tagName));
    }
    private Date getDateValue(Element ele, String tagName) {
        String startDateString = getTextValue(ele,tagName);
        DateFormat df = new SimpleDateFormat("MM/dd/yyyy");
        Date newDateString;
        try {
                startDate = df.parse(startDateString);
                newDateString = df.format(startDate);
            } catch (Exception e) {
            throw new EJBException(e);
           }
        return newDateString;
    }
}



Tuesday, 19 March 2013

Dependency relations




Determine the dependency relations among the following instructions:
I1: a=b+c;
I2: b=a+d;
I3: e=a/f;

Then, Read Sets & Write Sets of given Instruction
For I1,                         R1= {b, c}       W1= {a}
For I2,             R2= {a, d}       W2= {b}
For I3,             R3= {a, f}        W3= {e}

For Instructions I1 & I2

R1 ^ W2 = {b}            ; Anti Dependence
R2 ^ W1 = {a}            ; Flow Dependence
W1 ^ W2 = {}            

Therefore I1 & I2 are both Flow Dependent and Anti Dependent.

For Instruction I2 & I3

R2 ^ W3 = {}
R3 ^ W2 = {}
W2 ^ W3 = {}

Therefore instructions I2 & I3 are independent of each other, and can be run in parallel.

For Instruction I1 & I3

R1 ^ W3 = {}
R3 ^ W1 = {a}            ; Flow Dependence
W1 ^ W3 = {}

Therefore instructions I1 & I3 are Flow Dependent.



Sunday, 17 March 2013

Water Jug Problem

A Water Jug Problem: You are given two Jugs, a 4-gallon one and a 3-gallon one. Neither have any measuring markers on it. There is a pump that can be used to fill the jugs with water. How can you get exactly 2 gallons of water into the 4-gallon jug?

The state space for this problem can be described as the set of ordered pairs of integers (x, y), such that x=0, 1,2,3, or 4 and y = 0,1,2, 0r 3; x represents the number of gallons of water in the 4-gallon jug, and y represents the quality of water in the 3-gallon jug. The Start State is (0,0). The goal state is (2,n) for any value of n (since the problem does not specify how many gallons need to be in the 3-gallon jug).

1 (x, y) 
If x < 4 -> (4,y) Fill the 4-gallon jug.
 

2. (x, y)  If y < 3 -> (x,3) Fill the 3-gallon jug.

3 (x, y) 
If x >0 -> (x – d, y) Pour some water out of the 4-gallon jug

4 (x, y) 
If y > 0 -> (x, y - d) pour some water out of the 3-Gallon jug

5 (x, y)
If x > 0 -> (0, y) Empty the 4-gallon jug on the ground

6 (x, y)
If y > 0 -> (x, 0) Empty the 3-gallon jug on the ground

7 (x, y)
If x + y> 4 and y > 0 -> (4,y – (4 -x)) ;pour some water from the 3-Gallon jug in to the
 4 - gallon jug until the 4 -gallon jug is full.

8 (x, y)
If x + y> 3 and x > 0  -> (x-(3-y),3) ;pour water from the 4 -Gallon jug in to the
3 -gallon jug until the 3 -gallon jug is full.

9. (x, y)
If x + y <4 and y > 0 -> (x+y,0) ;pour all the water from the 3-Gallon jug in to the
 4- gallon jug

10 (x, y)
If x + y < 3 and x > 0 -> (x+y,0)  ;pour all the water from the 4-Gallon jug in to the
 3- gallon jug 


11 (0,2) -> (2,0) ;pour all 2 gallons from the 3-Gallon jug in to the
4-Gallon jug.


12. (2,y) -> (0,y) ;Empty the 2 gallons in the 4.gallons in the 4-gallon jug on the
Ground.

Production rules for the water jug problem.

Gallons of water in the 4-gallon jug. Gallons of water in the 3-gallon jug Rule Applied
0 0 2
0 3 9
3 0 2
3 3
4 2 7
0 2 5 0r 12
2 0 9 or 11

One solution for the water jug problem.

0 0 2
4 0 1
1 3 8
1 0 6
0 1 10
4 1 1
2 3 8
2 0 6

Second solution for the water jug problem

Saturday, 16 March 2013

Sutherland Hodgman Polygon Clipping

Write C/C++ program to implement the Sutherland Hodgman polygon clipping algorithm. Using this program clip the polygon against the rectangular window. Make suitable assumptions.

#include <windows.h>
#include <gl/glut.h>

struct Point{
    float x,y;
} w[4],oVer[4];
int Nout;   

void drawPoly(Point p[],int n){
    glBegin(GL_POLYGON);           
    for(int i=0;i<n;i++)
        glVertex2f(p[i].x,p[i].y);   
    glEnd();
}

bool insideVer(Point p){   
        if((p.x>=w[0].x)&&(p.x<=w[2].x))       
            if((p.y>=w[0].y)&&(p.y<=w[2].y))
                return true;               
        return false;       
}

void addVer(Point p){       
    oVer[Nout]=p;       
    Nout=Nout+1;
}

Point getInterSect(Point s,Point p,int edge){
    Point in;           
    float m;
    if(w[edge].x==w[(edge+1)%4].x){ //Vertical Line       
        m=(p.y-s.y)/(p.x-s.x);   
        in.x=w[edge].x;               
        in.y=in.x*m+s.y;
    }
    else{//Horizontal Line           
        m=(p.y-s.y)/(p.x-s.x);   
        in.y=w[edge].y;
        in.x=(in.y-s.y)/m;       
    }   
    return in;
}

void clipAndDraw(Point inVer[],int Nin){
    Point s,p,interSec;   
    for(int i=0;i<4;i++)
    {
        Nout=0;
        s=inVer[Nin-1];
        for(int j=0;j<Nin;j++)
        {           
            p=inVer[j];
            if(insideVer(p)==true){               
                if(insideVer(s)==true){
                    addVer(p);                                   
                }
                else{
                    interSec=getInterSect(s,p,i);
                    addVer(interSec);                   
                    addVer(p);                   
                }
            }
            else{       
                if(insideVer(s)==true){
                    interSec=getInterSect(s,p,i);               
                    addVer(interSec);                                                   
                }
            }
            s=p;           
        }       
        inVer=oVer;       
        Nin=Nout;   
    }   
    drawPoly(oVer,4);
}

void init(){
    glClearColor(0.0f,0.0f,0.0f,0.0f);
    glMatrixMode(GL_PROJECTION);       
    glLoadIdentity();   
    glOrtho(0.0,100.0,0.0,100.0,0.0,100.0);
    glClear(GL_COLOR_BUFFER_BIT);   
    w[0].x =20,w[0].y=10;
    w[1].x =20,w[1].y=80;
    w[2].x =80,w[2].y=80;
    w[3].x =80,w[3].y=10;
}
void display(void){   
    Point inVer[4];
    init();
    // As Window for Clipping
    glColor3f(1.0f,0.0f,0.0f);       
    drawPoly(w,4);
    // As Rect
    glColor3f(0.0f,1.0f,0.0f);
    inVer[0].x =10,inVer[0].y=40;
    inVer[1].x =10,inVer[1].y=60;
    inVer[2].x =60,inVer[2].y=60;
    inVer[3].x =60,inVer[3].y=40;
    drawPoly(inVer,4);
    // As Rect
    glColor3f(0.0f,0.0f,1.0f);
    clipAndDraw(inVer,4);       
    // Print
    glFlush();
}

int main(int argc,char *argv[]){
    glutInit(&argc,argv);
    glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);
    glutInitWindowSize(400,400);
    glutInitWindowPosition(100,100);
    glutCreateWindow("Polygon Clipping!");
    glutDisplayFunc(display);
    glutMainLoop();
    return 0;
}

Friday, 15 March 2013

3D Transformation

4: Write a program in C/C++ using OpenGL to perform a 3-Dimensional transformation, such as translation ,rotation and reflection, on a given triangle.

#include <GL/glut.h> // GLUT stuff, includes OpenGL headers as well
#include <windows.h>
#include <math.h>

// Point class to keep it a little cleaner.
class Point {
public:
    float x, y, z;
    void setxy(float x2, float y2, float z2) { x = x2; y = y2; z=z2; }
    const Point & operator=(const Point &rPoint) {
         x = rPoint.x;
         y = rPoint.y;
         z = rPoint.z;
         return *this;
      }

};

void drawTriangle(Point p1, Point p2,Point p3) {       
    glBegin(GL_TRIANGLES);           
      glVertex3f(p1.x,p1.y,p1.z);//left of window
      glVertex3f(p2.x,p2.y,p2.z);
      glVertex3f(p3.x,p3.y,p3.z);     
    glEnd();//end drawing of line loop
    glFlush();   
}

void myDisplay() {
    Point abc[3];   
    glMatrixMode(GL_MODELVIEW); 
    glClearColor(0.0,0.0,0.0,0.0);     
    glClear(GL_COLOR_BUFFER_BIT);       
    glLoadIdentity();          
    abc[0].x=1.0,abc[0].y=-0.25,abc[0].z=0.0;
    abc[1].x=0.0,abc[1].y=-0.25,abc[1].z=0.0;
    abc[2].x=0.0,abc[2].y=0.25,abc[2].z=0.0;           
    drawTriangle(abc[0],abc[1],abc[2]);                   
    glTranslatef(0.0f,-0.6f,0.0f);
    drawTriangle(abc[0],abc[1],abc[2]);           
    glRotatef(180.0,0.0f,0.0f,1.0f);
    drawTriangle(abc[0],abc[1],abc[2]);   
   
}

int main(int argc, char *argv[]) {
    glutInit(&argc, argv);
    glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);
    glutInitWindowSize(640,480);
    glutInitWindowPosition(100,150);
    glutCreateWindow("3D Transformation");   
    glutDisplayFunc(myDisplay);
    glutMainLoop();
    return 0;
}

Thursday, 14 March 2013

Bezier curve using OpenGL

Write a C/C++ program to draw a Bezier curve having the control points as p0 (0, 0), P1 (2, 5), P2 (5, 9), P3 (10, 20). Calculate the coordinates of the points on the curve corresponding to the parameter u = 0.2, 0.4, 0.6.

#include <windows.h>
#include <GL/glut.h>
#include <math.h>

// Point class to keep it a little cleaner.
class Point {
public:
    float x, y;
    void setxy(float x2, float y2) { x = x2; y = y2; }
    const Point & operator=(const Point &rPoint) {
         x = rPoint.x;
         y = rPoint.y;        
         return *this;
      }

};

Point abc[4];

void myInit() {
    glClearColor(0.0,0.0,0.0,0.0);
    glColor3f(1.0,0.0,0.0);
    glPointSize(8.0);
    glMatrixMode(GL_PROJECTION);
    glLoadIdentity();
    gluOrtho2D(0.0,64.0,0.0,48.0);
}

void drawDot(int x, int y) {
    glBegin(GL_POINTS);
    glVertex2i(x,y);
    glEnd();
    glFlush();
}

void drawLine(Point p1, Point p2) {
    glBegin(GL_LINES);
    glVertex2f(p1.x, p1.y);
    glVertex2f(p2.x, p2.y);
    glEnd();
    glFlush();
}

// Calculate the next bezier point.
Point drawBezier(Point A, Point B, Point C, Point D, double t) {
    Point P;
    P.x = pow((1 - t), 3) * A.x + 3 * t * pow((1 -t), 2) * B.x + 3 * (1-t) * pow(t, 2)* C.x + pow (t, 3)* D.x;
    P.y = pow((1 - t), 3) * A.y + 3 * t * pow((1 -t), 2) * B.y + 3 * (1-t) * pow(t, 2)* C.y + pow (t, 3)* D.y;      
    return P;
}

void myDisplay() {
    glClear(GL_COLOR_BUFFER_BIT);   
    Point POld=abc[0];
    abc[0].x=0,abc[0].y=0;
    abc[1].x=2,abc[1].y=5;
    abc[2].x=5,abc[2].y=9;
    abc[3].x=10,abc[3].y=20;
    glColor3f(1.0,0.0,0.0);
    for(int i=0;i<4;i++)
        drawDot(abc[i].x, abc[i].y);       
    glColor3f(1.0,1.0,1.0);
    drawLine(abc[0], abc[1]);
    drawLine(abc[1], abc[2]);
    drawLine(abc[2], abc[3]);   
    for(double t = 0.0;t <= 1.0; t += 0.1) {
        Point P = drawBezier(abc[0], abc[1], abc[2], abc[3],  t);
        drawLine(POld, P);
        POld = P;       
    }
    glFlush();
}

int main(int argc, char *argv[]) {
    glutInit(&argc, argv);
    glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);
    glutInitWindowSize(640,480);
    glutInitWindowPosition(100,150);
    glutCreateWindow("Bezier Curve");   
    glutDisplayFunc(myDisplay);
    myInit();
    glutMainLoop();
    return 0;
}

Wednesday, 13 March 2013

DDA Algorithm using OpenGL

Write a C/C++ program (USING OpenGL) to implement DDA algorithm for line generation. Use this algorithm to draw a line with endpoints (2, 3) and (9, 8).

#include <windows.h>
#include <gl/glut.h>
#include <math.h>
#include <stdio.h>
const float PI=3.14;

void drawLine(int x0,int y0,int x1,int y1){
    glBegin(GL_POINTS);
    glColor3f(1.0,1.0,1.0);   
    double m=(double)(y1-y0)/(x1-x0);       
    double y=(double)y0;
    double x=(double)x0;
    if(m<1)    {       
        while(x<=x1)        {
            glVertex2d(x,floor(y));
            printf("%f %f\n",floor(y),x);
            y=y+m;
            x++;
        }
    }
    else    {
        double m1=1/m;
        while(y<=y1)        {
            glVertex2d(floor(x),y);           
            y++;
            x=x+m1;
        }
    }
    glEnd();
}

void init(void){   
    glClearColor(0.0,0.0,0.0,0.0);   
    glMatrixMode(GL_PROJECTION);
    glLoadIdentity();
    glOrtho(0.0,100.0,0.0,100,0.0,100.0);
}
void display(void)
{
    glClear(GL_COLOR_BUFFER_BIT);
    drawLine(2,3,9,8);   
    glutSwapBuffers();
}

int main(int argc, char** argv){
    glutInit(&argc,argv);
    glutInitDisplayMode(GLUT_DOUBLE|GLUT_RGB);
    glutInitWindowSize(100,100);
    glutInitWindowPosition(50,50);
    glutCreateWindow("DDA Line Drawing!");
    init();
    glutDisplayFunc(display);   
    glutMainLoop();
    return 0;
}

Using OpenGL

Write a program in C/C++ using OpenGL to draw a circle of red color
inside of a rectangle of blue color on a background of green colors.


#include <windows.h>
#include <gl/glut.h>
#include <math.h>
const float PI=3.14;

void drawCircle(){
    glBegin(GL_LINE_LOOP);
    glColor3f(1.0,0.0,0.0);
    for(int i =0; i <= 300; i++){
        double angle = 2 * PI * i / 300;
        double x = 5*cos(angle);
        double y = 5*sin(angle);
        glVertex2d(x,y);
    }
    glEnd();
}
void drawRect(){
    glColor3f(0.0,0.0,1.0);
    glRectf(-5.0,5.0,5.0,-5.0);
}
void init(void){   
    glClearColor(0.0,1.0,0.0,0.0);   
    glMatrixMode(GL_PROJECTION);
    glLoadIdentity();
    glOrtho(-10.0,10.0,-10.0,10.0,-10.0,10.0);
}
void display(void)
{
    glClear(GL_COLOR_BUFFER_BIT);
    drawRect();
    drawCircle();
    glutSwapBuffers();
}

int main(int argc, char** argv){
    glutInit(&argc,argv);
    glutInitDisplayMode(GLUT_DOUBLE|GLUT_RGB);
    glutInitWindowSize(320,320);
    glutInitWindowPosition(50,50);
    glutCreateWindow("2D Shapes");
    init();
    glutDisplayFunc(display);   
    glutMainLoop();
    return 0;
}

Assembly Code to Concatenate two Strings

Assembly Code to Concatenate two Strings

DATA SEGMENT
    STR1 DB "HELLO$"
    STR2 DB " INDIA$"
    STR DB ?
    TMP DW ?
DATA ENDS                        

CODE SEGMENT                
    ASSUME CS:CODE, DS:DATA
    ;SET LOOP COUNTER
    MOV CX, 5       
    ;ADDRESS OF STR1
    LEA BX, STR1   
    ;ADDRESS OF STR
    LEA AX, STR   
   
    AGAIN1:        
    ;PICK CHARACTER FROM BX(STR1)   
    MOV DL, [BX]   
    ;LOAD ADDRESS STR
    XCHG BX, AX      
    ;LOAD CHARACTER AT BX(STR)
    MOV [BX], DL             
    ;LOAD ADDRESS STR1
    XCHG AX, BX      
    ;INCREMENT STR1 ADDRESS
    INC BX               
    ;INCREMENT STR ADDRESS
    INC AX                             
    LOOP AGAIN1    
          
    ;ADDRESS OF STR1
    LEA BX, STR2  
    MOV CX, 6
   
    AGAIN2:        
    ;PICK CHARACTER FROM BX(STR21)   
    MOV DL, [BX]   
    ;LOAD ADDRESS STR
    XCHG BX, AX      
    ;LOAD CHARACTER AT BX(STR)
    MOV [BX], DL             
    ;LOAD ADDRESS STR2
    XCHG AX, BX      
    ;INCREMENT STR2 ADDRESS
    INC BX               
    ;INCREMENT STR ADDRESS
    INC AX                             
    LOOP AGAIN2
          
    ;LOAD ADDRESS OF STR                      
    XCHG BX, AX         
    ;END STR       
    MOV [BX], "!"
    INC BX
    MOV [BX], "$"     
   
    ;PRINT STR         
    MOV DX, OFFSET STR                      
    MOV AH, 09H
    INT 21H

CODE ENDS
                        
                        

Assembly Code to get BCD code

Assembly Code to get BCD code

;DATA PART
DATA SEGMENT
    N DB 34H,35H,24H ; SIMILART TO "45$"
DATA ENDS                              
;Code Part
CODE SEGMENT
    ASSUME CS: CODE, DS: DATA  
 

    ;get Address of N in BX register
    MOV BX, OFFSET N    
   
    ;fetch first byte to AL register           
    MOV AL, [BX]
    ;Shift bits to left by 4 positions
    SHL AL, 4               
    ;Save content of AL in DL register
    MOV DL, AL                     
   
    ;fetch second byte to AL register     
    MOV AL, [BX+1]                  
    ;Make left most 4 bits to 0
    AND AL, 0FH               
                 
    ;Add first byte in DL and Second Byte in AL
    ; to get packed BCD Code
    OR AL, DL              
   
    ;to print packed BCD code move it to DL register
    MOV DL, AL                                     
   
    ;Call DOS output interrupt                
    MOV AH, 02H
    INT 21H
CODE ENDS

Small Clinic Project in C++

Small Clinic Project in C++

Click here to download file...

Simple Class Diagram for Distance Education University Admission System

Simple Class Diagram for Distance Education University Admission System


Resize Control for change in Resolution


Resize Control for change in Resolution

Option Explicit
Public nHeight As Double
Public nWidth As Double
Dim nState As Boolean

Sub ResizeControls()
    Dim ctl As Control
    Dim wRatio As Double
    Dim hRatio As Double
    Dim fRatio As Double
On Error Resume Next
    If nState = True Then Exit Sub
    'Standard : 1024 * 728
    If Screen.Width = 15360 And Screen.Height = 11520 Then Exit Sub
    wRatio = Screen.Width / nWidth
    hRatio = Screen.Height / nHeight
    If UserControl.Parent.WindowState = 2 Then
        For Each ctl In UserControl.Parent
            ctl.Left = wRatio * ctl.Left
            ctl.Top = hRatio * ctl.Top
            ctl.Width = wRatio * ctl.Width
            ctl.Font.Size = ctl.Font.Size * hRatio
            ctl.Height = hRatio * ctl.Height
        Next
    End If
    nState = True
End Sub

Private Sub UserControl_ReadProperties(PropBag As PropertyBag)
    nHeight = UserControl.Parent.ScaleHeight
    nWidth = UserControl.Parent.ScaleWidth
    nState = UserControl.Parent.WindowState
End Sub

Fastest Functions to check whether a Table or Field exists in a Database (VB6)

Fastest Functions to check whether a Table or Field exists in a Database

Public Function isTableExists(con As ADODB.Connection, Table As String) As Boolean
On Error GoTo handle
    Dim rs As New ADODB.Recordset
    If rs.State = 1 Then rs.Close
    rs.Open "Select * from " & Table, conn, adOpenStatic, adLockReadOnly
    isTableExists= True
    Exit Function
handle:
    If Err.Number = -2147217865 Then
        isTableExists = False
    Else
        MsgBox Err.Description
    End If
End Function

Public Function isFieldExists(conn As ADODB.Connection, Table As String, field As String) As Boolean
On Error GoTo handle
    Dim rs As New ADODB.Recordset
    If rs.State = 1 Then rs.Close
    rs.Open "Select " & field & " from " & Table, conn, adOpenStatic, adLockReadOnly
    isFieldExists = True
    Exit Function
handle:
    If Err.Number = -2147217904 Then
        isFieldExists= False
    Else
        MsgBox Err.Description & Err.Number
    End If
End Function

Stack required for Evaluator (VB 6.0)

Stack required for Evaluator (VB 6.0)

Dim Stack(1000) As Variant
Dim vTop As Long
Const MaxValue = 1000

Sub push(value As Variant)
    If vTop >= MaxValue Then
        MsgBox "Stack OverFlow!", vbCritical, "Error!"
        Exit Sub
    Else
        vTop = vTop + 1
        Stack(vTop) = value
    End If
End Sub

Sub FlushStack()
    vTop = 0
End Sub

Function pop() As Variant
    If vTop > 0 Then
        pop = Stack(vTop)
        vTop = vTop - 1
    Else
        MsgBox "Stack Empty!", vbCritical, "Error!"
        Exit Function
    End If
End Function

Function IsEmpty() As Boolean
    If vTop = 0 Then
        IsEmpty = True
    Else
        IsEmpty = False
    End If
End Function

Function IsFilled() As Boolean
    If vTop = MaxValue Then
        IsFilled = True
    Else
        IsFilled = False
    End If
End Function

Evaluator in VB6.0

Evaluator in VB6.0


Option Explicit
Dim st As New Stack

Function Evaluate(ByVal str As String) As Double
    Dim word As String
    Dim i As Integer
    Dim A As Double
    Dim B As Double
    Dim C As Double
    st.FlushStack
    str = ChangeInPostFix(str)
    i = 1
    word = GetWord(str, i)
    Do While word <> ""
        Select Case Trim(word)
            Case "*"
                B = st.pop
                A = st.pop
                C = A * B
                st.push C
            Case "/"
                B = st.pop
                A = st.pop
                C = A / B
                st.push C
            Case "+"
                B = st.pop
                A = st.pop
                C = A + B
                st.push C
            Case "-"
                B = st.pop
                A = st.pop
                C = A - B
                st.push C
            Case Trim(word)
                st.push Val(word)
        End Select
        i = i + 1
        word = GetWord(str, i)
    Loop
    Evaluate = st.pop
End Function

Private Function ChangeInPostFix(ByVal str As String) As String
    Dim temp As String
    Dim word As String
    str = Trim(str)
    On Error GoTo handle
    If grid.Name <> "" Then str = ReplaceWithValue(str)
    Dim i As Integer
    i = 1
    st.push "("
    word = GetWord(str, i)
    Do While word <> ""
        Select Case Trim(word)
            Case "*"
                Do While HighPriority("*") = True
                    ChangeInPostFix = ChangeInPostFix & " " & st.pop
                Loop
                st.push "*"
            Case "/"
                Do While HighPriority("/") = True
                    ChangeInPostFix = ChangeInPostFix & " " & st.pop
                Loop
                st.push "/"
            Case "+"
                Do While HighPriority("+") = True
                    ChangeInPostFix = ChangeInPostFix & " " & st.pop
                Loop
                st.push "+"
            Case "-"
                Do While HighPriority("-") = True
                    ChangeInPostFix = ChangeInPostFix & " " & st.pop
                Loop
                st.push "-"
            Case "("
                st.push "("
            Case ")"
                temp = st.pop
                Do While temp <> "("
                    ChangeInPostFix = ChangeInPostFix & " " & temp
                    temp = st.pop
                Loop
            Case Trim(word)
                ChangeInPostFix = ChangeInPostFix & " " & Trim(word)
        End Select
        i = i + 1
        word = GetWord(str, i)
    Loop
    temp = st.pop
    Do While temp <> "("
        ChangeInPostFix = ChangeInPostFix & " " & temp
        temp = st.pop
    Loop
    Exit Function
handle:
    If Err.Number = 91 Then
        str = ""
    End If
End Function

Private Function HighPriority(opt1 As String) As Boolean
    Dim s As String
    If st.IsEmpty = False Then
        s = st.pop
        If pr(s) >= pr(opt1) Then
            HighPriority = True
        Else
            HighPriority = False
        End If
        Call st.push(s)
    End If
End Function

Private Function pr(str As String) As Integer
    Select Case str
        Case "*", "/"
            pr = 2
        Case "+", "-"
            pr = 1
        Case "("
            pr = 0
    End Select
End Function

Function GetWord(ByVal str As String, n As Integer)
    Dim word As String
    Dim i As Integer
    str = Trim(str)
    For i = 1 To n
        If InStr(1, str, " ") = 0 Then
            word = str
            str = ""
        Else
            word = Left(str, InStr(1, str, " "))
        End If
        If str <> "" Then str = Right(Trim(str), Len(str) - Len(word))
        str = Trim(str)
    Next i
    GetWord = word
End Function

Private Function GetToken(ByVal str As String) As Long
    Dim p1 As Integer
    Dim p2 As Integer
    Dim p3 As Integer
    Dim p4 As Integer
    Dim p5 As Integer
    Dim p6 As Integer
    Dim pos As Integer
    p1 = InStr(1, str, "/")
    p2 = InStr(1, str, "*")
    p3 = InStr(1, str, "+")
    p4 = InStr(1, str, "-")
    p5 = InStr(1, str, "(")
    p6 = InStr(1, str, ")")
    pos = GetSmall(p1, p2, p3, p4, p5, p6)
    GetToken = pos
End Function

Private Function GetSmall(ParamArray P()) As Long
    Dim i As Integer
    Dim Big As Long
    Dim value As Variant
    i = 0
    For Each value In P
        If P(i) < Big And P(i) <> 0 Then
            Big = P(i)
        ElseIf Big = 0 Then
            Big = P(i)
        End If
        i = i + 1
    Next
    GetSmall = Big
End Function

E-mail Program With Visual Basic (Require Base64 encryption)

E-mail Program With Visual Basic (Require Base64 encryption)

Dim fso As New Scripting.FileSystemObject
Dim fco As New Scripting.Encoder
Dim Sdata As String, Cptr As Integer
Dim StrArray As Variant, StrElement As Variant, MsgString As String
Dim v As Boolean
Dim o As Boolean

Private Sub Command1_Click()
    Winsock1.SendData "MAIL FROM:<yourID@YAHOO.in> " & vbCrLf
End Sub

Private Sub Timer1_Timer()
    Me.Caption = Winsock1.State
    If Winsock1.State = 9 Then Winsock1.Close
End Sub

Private Sub Winsock1_DataArrival(ByVal bytesTotal As Long)
    Dim str As String
    Call Winsock1.GetData(str)
    If Left(str, 3) = "220" Then
        Winsock1.SendData "EHLO YAHOO.COM " & vbCrLf
    ElseIf Left(str, 4) = "250-" Then
        Winsock1.SendData "AUTH LOGIN" & vbCrLf
    ElseIf str = "334 VXNlcm5hbWU6" & vbCrLf Then
        Winsock1.SendData "Encrypted ID" & vbCrLf
    ElseIf str = "334 UGFzc3dvcmQ6" & vbCrLf Then
        Winsock1.SendData "Encrypted Password" & vbCrLf
    ElseIf Left(str, 3) = "235" Then
        MsgBox "Authentication Succesfull!"
    ElseIf Left(str, 4) = "250 " And v = False Then
        Winsock1.SendData "RCPT To:<" & txtTo.Text & "> " & vbCrLf
        v = True
    ElseIf Left(str, 4) = "250 " Then
        If o = False Then
            Winsock1.SendData "DATA " & vbCrLf
            MsgBox "Data Sending!"
        Else
            Winsock1.SendData "QUIT" & vbCrLf
            MsgBox "OK Mail Sent!"
        End If
    ElseIf Left(str, 3) = "354" Then
        Winsock1.SendData "From: ""Sender"" <yourID@yahoo.in>" & vbCrLf
        Winsock1.SendData "To: ""Receiver"" <mailID@yahoo.com>" & vbCrLf
        Winsock1.SendData "Date: Fri, 31 Dec 2010 16:02:43 -0500" & vbCrLf
        Winsock1.SendData "Subject: " & Text2.Text & vbCrLf
        Call attachment
        For Each StrElement In StrArray
            Winsock1.SendData (CStr(StrElement) & vbCrLf)
        Next StrElement
        Winsock1.SendData "." & vbCrLf
        o = True
    End If
End Sub

Private Sub Winsock1_Error(ByVal Number As Integer, Description As String, ByVal Scode As Long, ByVal Source As String, ByVal HelpFile As String, ByVal HelpContext As Long, CancelDisplay As Boolean)
    MsgBox Number & " " & Description
End Sub

Sub attachment()
    If Len(txtAttachment.Text) = 0 Then
        'we don't need MIME for this
        MsgString = txtEmailBodyOfMessage.Text + vbCrLf
    Else
        'build the 1st part of the MIME script
        txtMimeCode = _
          "MIME-Version: 1.0 " + vbCrLf + _
          "Content-Type: multipart/mixed;" + vbCrLf + _
          " boundary=" + VbQuote + "------------060502030501040302050009" + VbQuote + vbCrLf + _
          vbCrLf _
          + "This is a multi-part message in MIME format." + vbCrLf + _
          "--------------060502030501040302050009" + vbCrLf + _
          "Content-Type: text/plain; charset=ISO-8859-1; format=flowed" + vbCrLf + _
          "Content-Transfer-Encoding: 7bit" + vbCrLf + _
          vbCrLf + _
          txtEmailBodyOfMessage + vbCrLf + _
          vbCrLf + _
          "--------------060502030501040302050009" + vbCrLf
        Select Case UCase(Right(txtAttachment.Text, 4))
        Case ".TXT"
          txtMimeCode = txtMimeCode + _
            "Content-Type: text/plain;" + vbCrLf + _
            "name=" + VbQuote + txtAttachment.Text + VbQuote + vbCrLf + _
            "Content-Transfer-Encoding: base64" + vbCrLf + _
            "Content-Disposition: attachment; filename=" + txtAttachment.Text + vbCrLf + _
            vbCrLf + _
            Base64Encode(RichTextBox1.Text) + vbCrLf + _
            vbCrLf + _
            "--------------060502030501040302050009--" + vbCrLf
        Case ".DOC"
          txtMimeCode = txtMimeCode + _
            "Content-Type: application/msword;" + vbCrLf + _
            "name=" + VbQuote + txtAttachment.Text + VbQuote + vbCrLf + _
            "Content-Transfer-Encoding: base64" + vbCrLf + _
            "Content-Disposition: attachment; filename=" + txtAttachment.Text + vbCrLf + _
            vbCrLf + _
            Base64Encode(RichTextBox1.Text) + vbCrLf + _
            vbCrLf + _
            "--------------060502030501040302050009--" + vbCrLf
          MsgString = txtMimeCode
        Case ".PDF"
          txtMimeCode = txtMimeCode + _
            "Content-Type: application/pdf;" + vbCrLf + _
            "name=" + VbQuote + txtAttachment.Text + VbQuote + vbCrLf + _
            "Content-Transfer-Encoding: base64" + vbCrLf + _
            "Content-Disposition: attachment; filename=" + txtAttachment.Text + vbCrLf + _
            vbCrLf + _
            Base64Encode(RichTextBox1.Text) + vbCrLf + _
            vbCrLf + _
            "--------------060502030501040302050009--" + vbCrLf
          MsgString = txtMimeCode
        Case ".XLS"
          txtMimeCode = txtMimeCode + _
            "Content-Type: application/excel;" + vbCrLf + _
            "name=" + VbQuote + txtAttachment.Text + VbQuote + vbCrLf + _
            "Content-Transfer-Encoding: base64" + vbCrLf + _
            "Content-Disposition: attachment; filename=" + txtAttachment.Text + vbCrLf + _
            vbCrLf + _
            Base64Encode(RichTextBox1.Text) + vbCrLf + _
            vbCrLf + _
            "--------------060502030501040302050009--" + vbCrLf
          MsgString = txtMimeCode
        Case Else
          txtMimeCode = txtMimeCode + _
            "Content-Type: application/unknown;" + vbCrLf + _
            "name=" + VbQuote + txtAttachment.Text + VbQuote + vbCrLf + _
            "Content-Transfer-Encoding: base64" + vbCrLf + _
            "Content-Disposition: attachment; filename=" + txtAttachment.Text + vbCrLf + _
            vbCrLf + _
            Base64Encode(RichTextBox1.Text) + vbCrLf + _
            vbCrLf + _
            "--------------060502030501040302050009--" + vbCrLf
          MsgString = txtMimeCode
        End Select
      End If
      MsgString = txtMimeCode
      StrArray = Split(MsgString, vbCrLf)
End Sub


Sunday, 10 March 2013

Download Punjabi Typing Tutor(Anmol lipi) made in C++ (No Source Code)
Punjabi Typing Tutor made in C++ (NO SOURCE CODE)

JSP Custom Tag Example

Q. Create a custom tag that will accept a full
name and convert into initials. For example Surendra Kumar Sharma
should be displayed as S.K. Sharma.
 Sol.
java file
package univ.myClasses;
import javax.servlet.jsp.JspWriter;
import javax.servlet.jsp.JspException;
import javax.servlet.jsp.tagext.JspFragment;
import javax.servlet.jsp.tagext.SimpleTagSupport;

/**
 * @author Navdeep
 */
public class ShortNameTagHandler extends SimpleTagSupport {
    private String name;

    @Override
    public void doTag() throws JspException {
        JspWriter out = getJspContext().getOut();
       
        try {           
            JspFragment f = getJspBody();           
            if (f != null)                 f.invoke(out);               
           
            out.print(shortName(name));
        } catch (java.io.IOException ex) {
            throw new JspException("Error in ShortNameTagHandler tag", ex);
        }
    }
    public String shortName(String name)
    {
            String sName="";
            String words[]=name.split(" ");                 
            for(String word:words)               
                sName=sName + word.substring(0, 1) + ".";        
            return sName;
    }
    public void setName(String name) {
        this.name = name;
    }
}

Tld file
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE taglib PUBLIC "-//Sun Microsystems, Inc.//DTD JSP Tag Library 1.2//EN" "http://java.sun.com/dtd/web-jsptaglibrary_1_2.dtd">

<taglib>
  <tlibversion>1.0</tlibversion>
  <jspversion>1.1</jspversion>
  <shortname>csajsp</shortname>
  <uri>csajsp-taglib</uri>
  <info>A tag library.</info>
  <tag>
    <name>shortName</name>
    <tag-class>univ.myClasses.ShortNameTagHandler</tag-class>
    <body-content>scriptless</body-content>
    <attribute>
      <name>name</name>
      <required>true</required>
      <rtexprvalue>true</rtexprvalue>
      <type>java.lang.String</type>
    </attribute>
  </tag>
</taglib>

jsp File

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
    <head>
        <%@taglib uri="csajsp-taglib.tld" prefix="csajsp" %>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Test Page</title>
    </head>
    <body>
                    <csajsp:shortName name="Surendra Kumar " /> Sharma
    </body>
</html>